Planet X, yeah no neah?

PLANET X

This one is even freaking ME out.
If you go to my final conclusion,
I mention a numeration that kept popping up in the derivations,
and I could not figure out why,
untill I noticed that this decimal was exactly.....one half...
of the [18 /19.5] degree angle,
and performed a profuse extrapolation of that number.

I also mentioned in my document that if Planet X exists,
it will be accounted for in the Omkulkancoatl Codex.

Don't ask me how this comes to me,
I wake up in the morning, get an idea,
pull out the calculator and Bingo.

ANGLES
[18 /19.5]= [.923076923].......this I have been rounding to [.923077]
but not this time!

So [.923076923] divided by two =[0. 4615384615]...remember that

So I took the legendary sidereal of Planet X of 3600 years,
and to get the days of the sidereal I multiplied that by
[364] day Earth Lunar Year.

[364]days x [3600]years= [1,310,400] days....that is a lot of days,
THEN
I applied the Mars radius equation of mine to that,
[X] x [Y] / [26.5]= [Z]
where X is the Mars radius and Y is the subject synodic or sidereal.
[Mars radius decimalized] x [ Planet X ] / 26.5= [Z]

[.339745] x [1310400]= [445201.848] / [26.5]degree angle= [16800]

ALSO [1310400] Planet X sidereal / 780M=.........................[1680]
go down the list of sidereals and synodics....heh...!!!
Here is one that screams!
Take the 845M J synodic of Mars -Jupiter during the 707 day sidereal

[1310400] / 845M J= [1550.769231]....x [19.5 / 18]degree angles=
.....................................................x [1.0833333]=............[1680]

.....what to do with that original number..............[16800] ?

For some reason immediately I decided to divide it back by
the Earth Lunar Year.

[16800] / [364] =[46.15384615]..........holy shit look back up to the top!
..........................[46.15384615]

[18 / 19.5] degree angle = [.923076923] / Pentad Pyramid EA length[2]=
.........................[.4615384615]

Now, I wonder if that is just coincidence...?

[16800]
Do I recognize it?
In passing the Vegisimal synodic of Jupiter in the 707 day sidereal,
in my document defined in the Mars-Jupiter synodic section,
is [20] x [42] = [840] + "5 days not part of that period" to equal=[845MJ.
[840] / pentad [5]= [168]
and 845MJ / 5.................=[169]=....[13] x [13]

I think this means that Planet X also arrives during the 707 day sidereal,
perhaps not every one of the 707 sidereals that occurs,
but when Planet X comes to wreak havoc,
it is during the 707 day sidereal most likely,
and let's hope that this does not mean
that it slips right thru that Stargate Vector when it opens,
and it suddenly just shows up.

Now check this out.
Take the [16800] and apply the [5] , [12] , [13] to it like I did in my document,
to many sidereala and synodics

[16800] / Pentad[5] = [3360].............[3360] is our main man
...see my random proofs on the [336].

Apply the [19.5 / 18] degree angles

[1.0833333] x [3360]=.......[3640] or TEN EARTH LUNAR YEARS

Ha!

And remember that the Mars Jupiter synodic of [845]M J
applied to the Mars radius formula was
[.339745] x [845] M J / [26.5] = [10.8333]
and that is TEN Times the [19.5 / 18] degree angles
*************************************************

Hey,
I am just saying that this is all NOT COINCIDENCE and CHANCE,
as defined by our esteemed NASA scientists. for Cydonia and the Pentad

NASA Geology

Wrong again.

The Grand Finale: Planet X Incoming

Planet X incoming.....[1310400]PX day sidereal

here it comes
[13] x [53] = [689]M sidereal in the ancient [13] heliosphere calendar
pentad [5] x [53] = [265]....[53] = [2 x 26.5]
Mars radius [.339745] x 780M= [265]

[1310400]PX / 689M= [1901.886792] x [26.5] = [50400]

...................[1310400]PX=................=[26] x [50400]

[26.5] x [26] = [689]M

[26.5 / 26]= [53 /52]= [265 / 260Tzolkin Earth calendar]

Planet X exists.

I bet that Planet X stuff went over the top eh?

I don't expect anyone to understand WHY the math works,
it just does,
because it is a calendar emanating from precise geometry
in the Pentad-12mouinds.

the point being that the way the numbers fall into place
so nice and evenly perfect is an indication that there is
a distinct mathematical system that is at play here,
emanating from the Pentad-Mars numerations.

These will be the last extrapolations I will attempt for awhile,
they kind of finish up Planet X.

On Planet X
one HAS TO USE tthe Lunar Earth Year of 364 days,
because it is a function of the [13]....x 28 days= [364]days
SEE MY DOCUMENT ON THIS

the 365.25 day Earth year does not work in the math.

Thus Planet X functions within the [13] heliospheric constant.
In days
............[13] x [100800]= [1310400]
So to quickly show how well the Planet X sidereal works:

My last post this number [16800] was achieved as such:

[X] x [Y] / [26.5]= [Z]
where X is the Mars radius and Y is the subject synodic or sidereal.
[Mars radius decimalized] x [ Planet X ] / 26.5= [Z]

[.339745] x [1310400]= [445201.848] / [26.5]degree angle= [16800]

NOW,
So [16800] / Pentad [5] =[3360].................................[3360]
Now Take
the orbit [sidereal] of Planet X at [1310400] / [39]=......[33600]
OR
[1310400]PX / 5pentad= [262080] / 780Msynodic=.......[336]

and [39] x [20] = 780M synodic is where my document began.

the other beauty of this 3600 year orbit of Nibiru in days,
as the function of the earth Lunar Year of [364]
is that the PX orbit vegisimalizes perfectly

[20] x [65520] = [1310400] PX days orbit
That [65520] does something grand, but that is pocket Aces for now.
-------------------------------------------------------------------------------

In my last post the PX math yielded this number.....[50400]
like this

[1310400] PX / 689M = [1901.886792] x [26.5] = [50400]
...................................[1310400] PX / [26]=......[50400]
[26.5] x [26] = [689]M
[26.5 / 26]= [53 /52]= [265 / 260Tzolkin Earth calendar]

Now take the orbit of Nibiru [1310400] / [260] Tzolkin calendar=
....................................................................[5040]

Interesting how the "numeric sets" repeat isn't it?
--------------------------------------------------------------

One last one for the road so to say

[1310400] PX / [13] = [100800]
[1310400] PX / [12]= [109200]................................[109200]

[100800] x [13/12] or the [19.5 / 18] degree angles= [109200]

[109200] / 780Mars synodic=.......... [140]
[109200] / [364] Earth Lunar Year = [300]
...................................[140] / [300]=..................[.4666666]

Now back to my original equation using the Tzolkin Mars radius
of [3397.45]
[.339745] x [364]Earth Lunar Year / [26.5]=...........[4.666686]

when the numeric sets match so close and repeat as evidence,
then this favors a valid Planet X.